对 y=x^2+3/x 求导
来源:百度知道 编辑:UC知道 时间:2024/06/26 02:24:51
分母有x怎么求啊?
注意:1/x就是x^(-1),求导时依然用(x^n)'=n*x^(n-1)
y=x^2+3/x
y'=(x^2)'+3*(x^(-1))'
=2x-3x^(-2)
=2x-3/x^2
(3/x)'=[3x^(-1)]'=3[x^(-1)]'=3(-1)x^(-2)=-3x^(-2)
所以y'=(x^2+3/x)'
=(x^2)'+(3/x)'
=2x-3x^(-2)
2X-3/X^2
3/X=3*X^-1=-3X^-2
y'=2x-3/(x^2)
3/x=3x^(-1)就可以按照整式来求导了
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